7m^2+39m-18=0

Solution for 7m^2+39m-18=0 equation:

7m^2+39m-18=0

a = 7; b = 39; c = -18;
Δ = b2-4ac
Δ = 392-4·7·(-18)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-45}{2*7}=\frac{-84}{14}
=-6
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+45}{2*7}=\frac{6}{14}
=3/7
$